SOLUTION: Word problem: Find two consecutive even integers such that the smaller integer subtracted from twice the larger gives a difference of 10. find the two even integers.
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Question 180286: Word problem: Find two consecutive even integers such that the smaller integer subtracted from twice the larger gives a difference of 10. find the two even integers.
I go the answers just by trial and error as: 6 & 8 but is there a formula to use for this problem? thanks Found 3 solutions by Mathtut, Earlsdon, ankor@dixie-net.com:Answer by Mathtut(3670) (Show Source):
You can put this solution on YOUR website! 2 CONSECUTIVE EVEN integers. that woud make the number 2 apart from each other.
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lets call one integer,the smaller, a and the other b. But we know that b is equal to a+2
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2(a+2)-a=10
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2a+4-a=10
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a=6
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b=a+2=8
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there ya go
You can put this solution on YOUR website! Let x = the smaller even integer and x+2 = the next consecutive even integer.
2(x+2)-x = 10 "...the smaller integer subtracted from twice the larger integer gives a difference of 10."
2x+4-x = 10
x+4 = 10
x = 6 and x+2 = 8
The two consecutive even integers are 6 and 8.
You can put this solution on YOUR website! Find two consecutive even integers such that the smaller integer subtracted from twice the larger gives a difference of 10. find the two even integers.
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Here's an easy way, write an equation for the statement
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let the two consecutive integers be: x, (x+2)
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"smaller integer subtracted from twice the larger gives a difference of 10.
2(x + 2) - x = 10
2x + 4 - x = 10
2x - x = 10 - 4
x = 6 and 8 are the integers
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