SOLUTION: I got this problem:
For a given two-digit positive integer, the tens digits is 5 greater than the units digit. the sum of the digits is 11. Find the integer.
I got so far thi
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-> SOLUTION: I got this problem:
For a given two-digit positive integer, the tens digits is 5 greater than the units digit. the sum of the digits is 11. Find the integer.
I got so far thi
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Question 180237: I got this problem:
For a given two-digit positive integer, the tens digits is 5 greater than the units digit. the sum of the digits is 11. Find the integer.
I got so far this:
x(!0(5) + y(!) = 11. But that i'm not going any where. Can you tell me please what is wrong with my reasoning and can solve this.
Thank you as always Answer by Mathtut(3670) (Show Source):
You can put this solution on YOUR website! lets call our positive integer ab. Remember this can be written like this
:
10a+b
:
a=b+5.....eq 1
a+b=11....eq 2
:
take a's value in eq 1 and plug it into eq 2
:
b+5+b=11
:
2b=6
:
:
:
our number is 83
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