SOLUTION: I am asking for help with these two equations. I did see them listed but need a more of a break to better understand how to solve them 6x+3y=12z (2x+y)/4=z

Algebra ->  Equations -> SOLUTION: I am asking for help with these two equations. I did see them listed but need a more of a break to better understand how to solve them 6x+3y=12z (2x+y)/4=z      Log On


   



Question 178556: I am asking for help with these two equations. I did see them listed but need a more of a break to better understand how to solve them
6x+3y=12z
(2x+y)/4=z

Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!

6x%2B3y=12z+--------> EQN 1
%282x%2By%29%2F4=z--------> EQN 2
?????? -----------------> EQN 3
.
Sorry, you need 3 EQUATIONS because you have 3 UNKNOWNS--->(x,y,z)
You can easily substitute EQN 2 in EQN 1, and that eliminates "z", but still you have 2 UNKNOWNS----> x & y.
.
Thank you,
Jojo