SOLUTION: 3y^2 + y - 5 = 0 How do you solve this?

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Question 177009: 3y^2 + y - 5 = 0 How do you solve this?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
You can graph it and look for zeros.
+graph%28+300%2C+300%2C+-3%2C+3%2C+-10%2C+10%2C+3x%5E2%2Bx-5%29+
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You can also calculate exact values using the quadratic formula,
y+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
y+=+%28-1+%2B-+sqrt%28+1%5E2-4%2A%283%29%2A%28-5%29+%29%29%2F%282%2A%283%29%29+
y+=+%28-1+%2B-+sqrt%28+1%2B60+%29%29%2F%286%29+
y+=+%28-1+%2B-+sqrt%28+61%29%29%2F%286%29+
or approximately,
y%5B1%5D=%28-1%2Bsqrt%2861%29%29%2F6=%28-1%2B7.81%29%2F6=6.81%2F6=1.14
y%5B2%5D=%28-1-sqrt%2861%29%29%2F6=%28-1-7.81%29%2F6=-8.81%2F6=-1.47