SOLUTION: Solve the equations A) 3a-3b=5 3-a=-2b B)x/2++y/4=-1/4 2x-y=2+y-x C)0.01x=0.12-0.04y 2x=4(3-2y) inconsistent systems D) x=-3y+6 2x+6y=12 dependant systems

Algebra ->  Equations -> SOLUTION: Solve the equations A) 3a-3b=5 3-a=-2b B)x/2++y/4=-1/4 2x-y=2+y-x C)0.01x=0.12-0.04y 2x=4(3-2y) inconsistent systems D) x=-3y+6 2x+6y=12 dependant systems      Log On


   

Question 172829: Solve the equations
A) 3a-3b=5
3-a=-2b
B)x/2++y/4=-1/4
2x-y=2+y-x
C)0.01x=0.12-0.04y
2x=4(3-2y) inconsistent systems
D) x=-3y+6
2x+6y=12 dependant systems
Answer by EMStelley(208) About Me  (Show Source):
You can put this solution on YOUR website!
I will do A) for you and that should help.
3a-3b=5
3-a=-2b
I am a fan of the addition method, so I will go with that. I first need to make the second equation look like the first by adding 2b to both sides and subtracting 3 from both sides.
So our two equations are now
3a-3b=5
-a%2B2b=-3
Now, notice that if I multiply the second equation by 3, that the a's will add up to 0.
3a-3b=5
-3a%2B6b=-9
Now, add the two together:
3b=-4
b=-4%2F3
To find a, you plug in b=-4/3 into either equation. I will use the first.
3a-3%28-4%2F3%29=5
3a%2B4=5
3a=1
a=1%2F3
So the solution is a=1/3, b=-4/3, or (1/3, -4/3).