SOLUTION: The width of a rectangular garden is 3yd more than twice its width. The perimeter of the rectangle is 36yd. What are the width and the length? Any assistance is appreciated.

Algebra ->  Equations -> SOLUTION: The width of a rectangular garden is 3yd more than twice its width. The perimeter of the rectangle is 36yd. What are the width and the length? Any assistance is appreciated.       Log On


   



Question 160723This question is from textbook
: The width of a rectangular garden is 3yd more than twice its width. The perimeter of the rectangle is 36yd. What are the width and the length?
Any assistance is appreciated. I am the dad and if I can see how this one is done I can figure out the rest. Thank you!
This question is from textbook

Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
The length of a rectangular garden is 3yd more than twice its width. The perimeter of the rectangle is 36yd. What are the width and the length?
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Let w = width
from "The length of a rectangular garden is 3yd more than twice its width." we get:
w+3 = length
.
Since:
length+length+width+width = perimeter
2length+2width = perimeter
2(length+width) = perimeter
.
substituting in our variables and info:
2(length+width) = perimeter
2((w+3)+w) = 36
2(w+3+w) = 36
2(2w+3) = 36
2w+3 = 18
2w = 15
w = 7.5 yards (width)
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length:
w+3 = 7.5+3 = 10.5 yards (length)