Question 152667: What is the equation of the line that passes through (4, -2) and is perpendicular to y = 1? @ The line that is perpendicular to y = 1 must be vertical, so it has undefined slope. Hence, it can only be the x coordinate of the defined point: x = 4.
a. y = ½x + 4
b. y = -2
c. Insufficient
d. none of the above
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! What is the equation of the line that passes through (4, -2) and is perpendicular to y = 1? @ The line that is perpendicular to y = 1 must be vertical, so it has undefined slope. Hence, it can only be the x coordinate of the defined point: x = 4.
a. y = ½x + 4
b. y = -2
c. Insufficient
d. none of the above
-------------------
y = 1 is a vertical line, parallel to the y axis, so a line perpendicular to it will be parallel to the y axis.
Since is passes thru (4,-2), y has to equal -2. So it's b, y = -2
|
|
|
