SOLUTION: The perimeter of a rectangle is 22m. The lenght is 5 more than twice the width. Find the dimesions.

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Question 151545: The perimeter of a rectangle is 22m. The lenght is 5 more than twice the width. Find the dimesions.
Answer by iluvbuilding429(41) About Me  (Show Source):
You can put this solution on YOUR website!
The perimeter of a rectangle is 22m. The lenght is 5 more than twice the width. Find the dimesions.
Use the formula:
P=2L%2B2w
Plug in your amount for the perimeter:
22=2L%2B2w
Since the length is 5 more than twice the width, L=2w+5. So, replace L with 2w+5:
22=2%282w%2B5%29%2B2w
Use the distributive property for the the parentheses:
22=4w%2B10%2B2w
Rearrange the terms so that you will be able to add the like terms:
22=4w%2B2w%2B10
Add the like terms:
22=6w%2B10
Subtract 10 from both sides:
12=6w
Divide both sides by 6:
2=w
This means the width is 2. To find the length (which is 2w+5), plug in the 2 for w.
L=2%282%29%2B5
Multiply:
L=4%2B5
Add:
L=9
So, the length is 9, and the width is 2.


-iluvbuilding429