SOLUTION: 5t^-16t=-12 i have tried everything. please help me. I am so greatful for this site and your time. thank you so much. This is factoring equations.

Algebra ->  Equations -> SOLUTION: 5t^-16t=-12 i have tried everything. please help me. I am so greatful for this site and your time. thank you so much. This is factoring equations.      Log On


   



Question 149304: 5t^-16t=-12
i have tried everything. please help me. I am so greatful for this site and your time. thank you so much. This is factoring equations.

Found 2 solutions by jim_thompson5910, vleith:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
5t%5E2-16t=-12 Start with the given equation.


5t%5E2-16t%2B12=0 Add 12 to both sides.


Now let's factor the left side






Looking at the expression 5t%5E2-16t%2B12, we can see that the first coefficient is 5, the second coefficient is -16, and the last term is 12.


Now multiply the first coefficient 5 by the last term 12 to get %285%29%2812%29=60.


Now the question is: what two whole numbers multiply to 60 (the previous product) and add to the second coefficient -16?


To find these two numbers, we need to list all of the factors of 60 (the previous product).


Factors of 60:
1,2,3,4,5,6,10,12,15,20,30,60
-1,-2,-3,-4,-5,-6,-10,-12,-15,-20,-30,-60


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to 60.
1*60
2*30
3*20
4*15
5*12
6*10
(-1)*(-60)
(-2)*(-30)
(-3)*(-20)
(-4)*(-15)
(-5)*(-12)
(-6)*(-10)

Now let's add up each pair of factors to see if one pair adds to the middle coefficient -16:


First NumberSecond NumberSum
1601+60=61
2302+30=32
3203+20=23
4154+15=19
5125+12=17
6106+10=16
-1-60-1+(-60)=-61
-2-30-2+(-30)=-32
-3-20-3+(-20)=-23
-4-15-4+(-15)=-19
-5-12-5+(-12)=-17
-6-10-6+(-10)=-16



From the table, we can see that the two numbers -6 and -10 add to -16 (the middle coefficient).


So the two numbers -6 and -10 both multiply to 60 and add to -16


Now replace the middle term -16t with -6t-10t. Remember, -6 and -10 add to -16. So this shows us that -6t-10t=-16t.


5t%5E2%2Bhighlight%28-6t-10t%29%2B12 Replace the second term -16t with -6t-10t.


%285t%5E2-6t%29%2B%28-10t%2B12%29 Group the terms into two pairs.


t%285t-6%29%2B%28-10t%2B12%29 Factor out the GCF t from the first group.


t%285t-6%29-2%285t-6%29 Factor out 2 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%28t-2%29%285t-6%29 Combine like terms. Or factor out the common term 5t-6



So 5t%5E2-16t%2B12 factors to %28t-2%29%285t-6%29.


Note: you can check to see if you did it right by FOILing %28t-2%29%285t-6%29 to get 5t%5E2-16t%2B12.



So 5t%5E2-16t%2B12=0 becomes %28t-2%29%285t-6%29=0.



Now set each factor equal to zero:


t-2=0 or 5t-6=0

t=2 or t=6%2F5 Now solve for t in each case


So our answers are

t=2 or t=6%2F5

Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
Given : 5t%5E2-16t+=+-12
5t%5E2+-16t+%2B+12+=+0
the factor of 5 are 1 and 5. The factors of 12 are 1,12 and 2,6 and 3,4. We need to find the combination that provides a sum or -16.
16 = (2*5 + 1*6)
5t%5E2+-+16t+%2B12+=+0
%285t+-+6%29%28t+-+2%29+=+0
Using the rule of zero, either one of the other term can be zero and the product is zero. So
Either {{5t - 6 = 0}}} or t+-+2+=+0
Thus
t = 6/5 or t = 2

See this URL --> http://www.hostsrv.com/webmab/app1/MSP/quickmath/02/pageGenerate?site=quickmath&s1=algebra&s2=factor&s3=basic
Note that you must use x as the variable (just use x instead of t)