SOLUTION: use the graph of the giveb function to find any relative maxima and relative minima. f(x)=x^3-3x^2+1 a)maximum:none;minimum:(2,-3) b)no maximum or minimum c)maximum:(0,1);min

Algebra ->  Equations -> SOLUTION: use the graph of the giveb function to find any relative maxima and relative minima. f(x)=x^3-3x^2+1 a)maximum:none;minimum:(2,-3) b)no maximum or minimum c)maximum:(0,1);min      Log On


   



Question 147749: use the graph of the giveb function to find any relative maxima and relative minima.
f(x)=x^3-3x^2+1
a)maximum:none;minimum:(2,-3)
b)no maximum or minimum
c)maximum:(0,1);minimum:nopne
d))maximum:(0,1);minimum:(2,-3)
I think its d but not positive.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
use the graph of the giveb function to find any relative maxima and relative minima.
f(x)=x^3-3x^2+1
a)maximum:none;minimum:(2,-3)
b)no maximum or minimum
c)maximum:(0,1);minimum:nopne
d))maximum:(0,1);minimum:(2,-3)
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graph%28400%2C300%2C-10%2C10%2C-10%2C10%2Cx%5E3-3x%5E2%2B1%29
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Ans: d is correct
Cheers,
Stan H.