SOLUTION: solve the absolute calue inequality. other than 0, use interval notation to express the solution set and graph the solution set on a number line |2y+6/3|<2

Algebra ->  Equations -> SOLUTION: solve the absolute calue inequality. other than 0, use interval notation to express the solution set and graph the solution set on a number line |2y+6/3|<2      Log On


   



Question 147744: solve the absolute calue inequality. other than 0, use interval notation to express the solution set and graph the solution set on a number line
|2y+6/3|<2

Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
solve the absolute calue inequality. other than 0, use interval notation to express the solution set and graph the solution set on a number line
|2y+6/3|<2


Here are the rules for removing the absolute value bars in an
absolute value inequality of the form 

1.  For cases of the form abs%28expression%29%3CA where A is 
    a positive number, write this:

                      -A%3Cexpression%3CA     
                      
    
2.  For cases of the form abs%28expression%29%3C=A where A is a
    positive number, write this:

                      -A%3C=expression%3C=A     
                      

3.  For cases of the form abs%28expression%29%3EA where A is a 
    positive number, write this:
             
               -A%3CexpressionORexpression%3EA  

4.  For cases of the form abs%28expression%29%3E=A where A is a
    positive number, write this:
             
               -A%3C=expressionORexpression%3E=A 

Your problem:

abs%28%282y%2B6%29%2F3%29%3C2 is case 1, so to remove the absolute value symbols,
we write:

-2%3C%282y%2B6%29%2F3%3C2

Now we multiply all three sides by 3 to clear of the fraction:

-2%2A3%3C3%2A%282y%2B6%29%2F3%3C2%2A3

-2%2A3%3Ccross%283%29%2A%282y%2B6%29%2Fcross%283%29%3C2%2A3

-6%3C2y%2B6%3C6

Subtract 6 from all three sides:

-6-6%3C2y%2B6-6%3C6-6

-12%3C2y%3C0

Divide all three sides by 2 to solve for y
in the middle:

%28-12%29%2F2%3C%282y%29%2F2%3C0%2F2

%28-12%29%2F2%3C%28cross%282%29y%29%2Fcross%282%29%3C0%2F2

-6%3Cy%3C0

Mark -6 and 0 with open circles

<--------------o-----------------o------------>
 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1  0  1  2  3  4  

Now shade between them:

<--------------o=================o------------>
 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1  0  1  2  3  4

In interval notation that is written (-6,0)

Edwin