SOLUTION: y = log π is equivalent to:
a. 10^-y = π
b. 10^π = y
c. 10^y = π
d. Cannot be defined without first knowing the base of the logarithm
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Equations
-> SOLUTION: y = log π is equivalent to:
a. 10^-y = π
b. 10^π = y
c. 10^y = π
d. Cannot be defined without first knowing the base of the logarithm
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