SOLUTION: If 9y^2+kyz+16z^2 is a perfect square find a value of k
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Question 144409
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If 9y^2+kyz+16z^2 is a perfect square find a value of k
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(a+b)^2=a^2+2ab+b^2.
So, we have:
(3y)^2+kyz+(4z)^2
Identify: a=3y; b=4z.
Thus, 2*a*b=kyz
implies 2*3y(4z)=kyz
implies 24=k.
This gives
as the final expression, which would factor as (3y+4z)^2.