Question 144372: Solve this system of equations
18x - 7y = 121
6x - 14y = 122
Found 2 solutions by Alan3354, Edwin McCravy: Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! 18x-7y=121
6x-14y=122
Eliminate one variable. To do this multiply or divide one equation to make the coefficients of one of the variables the same as in the other eqn. Divide ean 2 by 2.
18x-7y=121
3x-7y=61
Subtract eqn 2 from eqn 1.
18x-7y=121
3x -7y=61
15x =60
x = 4
Substitute x in any eqn, and get y = -7
Answer by Edwin McCravy(20055) (Show Source):
You can put this solution on YOUR website! Solve this system of equations
18x - 7y = 121
6x - 14y = 122
You can make the x's cancel, by multiplying
every term of the second one by -3, for then
the 6x on the bottom equation will become a
-18x and that will cancel with the 18x in the
first equation. So we multiply every term of
6x - 14y = 122
by -3, and that makes it become
-18x + 42y = -366
Now write that under the original first equation:
18x - 7y = 121
-18x + 42y = -366
draw a line underneath and add equals to
equals:
18x - 7y = 121
-18x + 42y = -366
-----------------
0x + 35y = -245
Drop the 0x
35y = -245
Divide both sides by 35
y = -7
So that's the answer for y.
Next we start all over again and make the
y's cancel:
18x - 7y = 121
6x - 14y = 122
You can make the y's cancel, by multiplying
every term of the first one by -2, for then
the -7y in the top equation will become a
+14y and that will cancel with the -14y in the
bottom equation. So we multiply every term of
18x - 7y = 121
by -2, and that makes it become
-36x + 14y = -242
Now write that above the original bottom equation:
-36x + 14y = -242
6x - 14y = 122
draw a line underneath and add equals to
equals:
-36x + 14y = -242
6x - 14y = 122
-----------------
-30x + 0y = -120
Drop the 0y
-30x = -120
Divide both sides by -30
y = 4
So the answer is
(x,y) = (-7,4)
When you graph the two lines,
18x - 7y = 121
6x - 14y = 122
Now draw a vertical line from the point where they intersect
directly upward to the x-axis:
Notice that it ends right at 4 on the x-axis,
so that checks with x = 4
Now draw a horizontal line from the point where they intersect
directly leftward to the y-axis:
Notice that it ends right at -7 on the y-axis,
and that checks with y = -7
Edwin
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