SOLUTION: An astronaut on the moon tosses a ball upwards; when will the ball initially be 35 feet above the lunar surface if the ball's height (feet) follow:
h(t) = -2.6t^2 = 32.1t + 5.5, a
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-> SOLUTION: An astronaut on the moon tosses a ball upwards; when will the ball initially be 35 feet above the lunar surface if the ball's height (feet) follow:
h(t) = -2.6t^2 = 32.1t + 5.5, a
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Question 144115: An astronaut on the moon tosses a ball upwards; when will the ball initially be 35 feet above the lunar surface if the ball's height (feet) follow:
h(t) = -2.6t^2 = 32.1t + 5.5, and t is in seconds from release?
a. 1 second
b. 2 seconds
c. 1/2 seconds
d. 13.2 seconds
I selected 1 second (a) Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! An astronaut on the moon tosses a ball upwards; when will the ball initially be 35 feet above the lunar surface if the ball's height (feet) follow:
h(t) = -2.6t^2 + 32.1t + 5.5, and t is in seconds from release?
a. 1 second
b. 2 seconds
c. 1/2 seconds
d. 13.2 seconds
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EQUATION:
-2.6t^2+32.1t + 5.5 = 35
-2.6t^2+32.1t-29.5 = 0
Since the coefficients add up to zero, x=1 is a zero.
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Answer: a
You are correct
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Cheers,
stan H.
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