SOLUTION: A customer received change worth $18.95. He receives 10 more dollar coins than 25cent peices and 22 more 10cent pieces than 25cent pieces. how many coins of each did he receive?

Algebra ->  Equations -> SOLUTION: A customer received change worth $18.95. He receives 10 more dollar coins than 25cent peices and 22 more 10cent pieces than 25cent pieces. how many coins of each did he receive?      Log On


   

Question 143219: A customer received change worth $18.95. He receives 10 more dollar coins than 25cent peices and 22 more 10cent pieces than 25cent pieces. how many coins of each did he receive?
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
let x="25 cent pieces", so x+10="dollar coins" and x+22="10 cent pieces"

working in cents to avoid decimal points

x(25)+(x+10)(100)+(x+22)(10)=1895 __ 25x+100x+1000+10x+220=1895 __ 135x+1220=1895

135x=675 __ x=5