SOLUTION: solve the equation for y 2y^2+y+8=(y-2)^2

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Question 136612: solve the equation for y
2y^2+y+8=(y-2)^2
Answer by solver91311(24713) About Me  (Show Source):
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Expand the binomial on the right, put the equation into standard form (everything on the left set equal to zero), collect like terms, and then solve by either factoring and using the Zero Product Rule, completing the square, or using the quadratic formula.