SOLUTION: SOLVE THE SYSTEM USING THE GAUSS-JORDAN METHOD PROBLEM: 2x-y= 0 x+y= 3 I'M STILL VERY CONFUSED BY THE SOLVING PROCESS.. I DO UNDERSTAND THE BASIC FORMULA [ 1 0.. AND

Algebra ->  Equations -> SOLUTION: SOLVE THE SYSTEM USING THE GAUSS-JORDAN METHOD PROBLEM: 2x-y= 0 x+y= 3 I'M STILL VERY CONFUSED BY THE SOLVING PROCESS.. I DO UNDERSTAND THE BASIC FORMULA [ 1 0.. AND      Log On


   



Question 136220: SOLVE THE SYSTEM USING THE GAUSS-JORDAN METHOD
PROBLEM: 2x-y= 0
x+y= 3
I'M STILL VERY CONFUSED BY THE SOLVING PROCESS.. I DO UNDERSTAND THE BASIC FORMULA [ 1 0.. AND BENEATH THAT IS 0 1..] AND I DO UNDERSTAND HOW TO FIRST SET IT UP... [ 2 -1..0]
[ 1 1..3]
YET FROM HERE I JUST GET FRUSTRATED AND IT SEEMS LIKE NO MATTER HOW MANY TIMES I TRY, I GET NOWHERE.. PLEASE HELP.. THANK YOU SO MUCH, lj23kfuller@yahoo.com

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
%28matrix%282%2C3%2C2%2C-1%2C0%2C1%2C1%2C3%29%29


Swap row 1 and row 2:
%28matrix%282%2C3%2C1%2C1%2C3%2C2%2C-1%2C0%29%29

Multiply row 1 by -2, then add the result to row 2, replacing row 2 with the result:
Row 1 times -2 is -2, -2, -6
Result added to row 2 is 2-2=0, -1-2=-3, 0-6=-6, so:
%28matrix%282%2C3%2C1%2C1%2C3%2C0%2C-3%2C-6%29%29

Multiply row 2 by -1%2F3 and replace row 2 with the result:
%28matrix%282%2C3%2C1%2C1%2C3%2C0%2C1%2C2%29%29

Multiply row 2 by -1, then add the result to row 1, replacing row 1 with the result:
Row 2 times -1 is 0, -1, -2
Result added to row 1 is 1+0=1, 1-1=0, 3-2=1, so:
%28matrix%282%2C3%2C1%2C0%2C1%2C0%2C1%2C2%29%29

So:
x=1 and y=2