SOLUTION: Please explain how you would solve this equation: 20b^2+33b-4=-14

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Question 132770: Please explain how you would solve this equation:
20b^2+33b-4=-14
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
20b%5E2%2B33b-4=-14 Start with the given equation


20b%5E2%2B33b-4%2B14=0 Add 14 to both sides.


20b%5E2%2B33b%2B10=0 Combine like terms


%284b%2B5%29%285b%2B2%29=0 Factor the left side (note: if you need help with factoring, check out this solver)



Now set each factor equal to zero:
4b%2B5=0 or 5b%2B2=0

b=-5%2F4 or b=-2%2F5 Now solve for b in each case


So our solutions are

b=-5%2F4 or b=-2%2F5