SOLUTION: Tutor could you please help me with the following problem: x+4y=16
If both x and y are positive integers in this equation, how many different values can x have? (1,2, 3 or 4)
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If both x and y are positive integers in this equation, how many different values can x have? (1,2, 3 or 4)
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Question 128929: Tutor could you please help me with the following problem: x+4y=16
If both x and y are positive integers in this equation, how many different values can x have? (1,2, 3 or 4) I chose 3..am I correct?
Thank you for your help! Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! X+4Y=16
3+4Y=16
4Y=16-3
4Y=13
Y=13/4 WRONG ANSWER FOR Y.
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4+4Y=16
4Y=16-4
4Y=12
Y=3 ONLY ONE THAT WORKS.
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