SOLUTION: I can't figure this out at all. Problem #44 states: Suppose {{{(1*10^a)+(2*10^b)+(3*10^c)+(4*10^d)=24130}}}, and a,b,c and d are all positive integers. Find the value of {{{(a+b+c

Algebra ->  Equations -> SOLUTION: I can't figure this out at all. Problem #44 states: Suppose {{{(1*10^a)+(2*10^b)+(3*10^c)+(4*10^d)=24130}}}, and a,b,c and d are all positive integers. Find the value of {{{(a+b+c      Log On


   

Question 128537This question is from textbook Pre-Algebra
: I can't figure this out at all.
Problem #44 states: Suppose %281%2A10%5Ea%29%2B%282%2A10%5Eb%29%2B%283%2A10%5Ec%29%2B%284%2A10%5Ed%29=24130, and a,b,c and d are all positive integers. Find the value of %28a%2Bb%2Bc%2Bd%29%2F16.
I don't even know how to begin. I understood this chapter up to this question.
Thanks. This question is from textbook Pre-Algebra

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Remember, the number 24,130 can be broken up like this:









So this shows us that which means . Also, which means . This continues until you run out of variables.

So we have the values

a=2, b=4, c=1, and d=3



So %28a%2Bb%2Bc%2Bd%29%2F16 becomes %282%2B4%2B1%2B3%29%2F16=10%2F16=5%2F8