SOLUTION: A small company produces both bouquets and wreaths of dried flowers. The bouquets take 1 hour of labor to produce, and the wreaths take 2 hours. The labor available is limited to 8
Algebra ->
Equations
-> SOLUTION: A small company produces both bouquets and wreaths of dried flowers. The bouquets take 1 hour of labor to produce, and the wreaths take 2 hours. The labor available is limited to 8
Log On
Question 127659: A small company produces both bouquets and wreaths of dried flowers. The bouquets take 1 hour of labor to produce, and the wreaths take 2 hours. The labor available is limited to 80 hours per week, and the total production capacity is 60 items per week. Write a system of inequalities representing this situation, where x is the number of bouquets and y is the number of wreaths. Then graph the system of inequalities.
So far I have come up with
x+y<=60 and x+2y<=80
x>40
Y>20
With these numbers I am not sure how to graph them.
y<=-x+60
y<=x/2 +40
I have confused myself, not sure which way to go. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A small company produces both bouquets and wreaths of dried flowers. The bouquets take 1 hour of labor to produce, and the wreaths take 2 hours. The labor available is limited to 80 hours per week, and the total production capacity is 60 items per week. Write a system of inequalities representing this situation, where x is the number of bouquets and y is the number of wreaths. Then graph the system of inequalities.
So far I have come up with
Quantity Inequality: x+y<=60
Labor Inequality: x+2y<=80
-----------
x>=0 ; y>=0
--------------
Solve both inequalities for "y":
y<=-x+60
y<= (-1/2)x +40
-------------------
Graph the "equality" statements which are the boundaries for the inequalities.
------------------------
Cheers,
Stan H.