SOLUTION: Please help. z^2-64/z divided by z-8/z+1

Algebra ->  Equations -> SOLUTION: Please help. z^2-64/z divided by z-8/z+1      Log On


   



Question 127401: Please help.
z^2-64/z divided by z-8/z+1

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
%28%28z%5E2-64%29%2F%28z%29%29%2F%28%28z-8%29%2F%28z%2B1%29%29 Start with the given expression

%28%28z%5E2-64%29%2F%28z%29%29%2A%28%28z%2B1%29%2F%28z-8%29%29 Multiply the first fraction by the reciprocal of the second fraction


%28%28%28z%2B8%29%28z-8%29%29%2F%28z%29%29%28%28z%2B1%29%2F%28z-8%29%29 Factor z%5E2-64 to get %28z%2B8%29%28z-8%29


%28z%2B8%29%28z-8%29%28z%2B1%29%2F%28z%29%28z-8%29 Combine the fractions


%28z%2B8%29cross%28%28z-8%29%29%28z%2B1%29%2F%28z%29cross%28%28z-8%29%29 Cancel like terms


%28z%2B8%29%28z%2B1%29%2Fz Simplify


--------------------------------------------------
Answer:

So %28%28z%5E2-64%29%2F%28z%29%29%28%28z%2B1%29%2F%28z-8%29%29 simplifies to %28z%2B8%29%28z%2B1%29%2Fz. In other words %28%28z%5E2-64%29%2F%28z%29%29%28%28z%2B1%29%2F%28z-8%29%29=%28z%2B8%29%28z%2B1%29%2Fz