SOLUTION: Graph the inequality 2x+3y>6 I start out by changing it to 3y=2x+6 divide each side by 3 resulting in y= 2/3x +2 are my coordinates (3,2) and (1,2) ?

Algebra ->  Equations -> SOLUTION: Graph the inequality 2x+3y>6 I start out by changing it to 3y=2x+6 divide each side by 3 resulting in y= 2/3x +2 are my coordinates (3,2) and (1,2) ?      Log On


   



Question 127094This question is from textbook Beginning Algebra
: Graph the inequality
2x+3y>6
I start out by changing it to
3y=2x+6
divide each side by 3 resulting in
y= 2/3x +2
are my coordinates (3,2) and (1,2) ?
This question is from textbook Beginning Algebra

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
I don't see what you're doing
If it's an inequality, that's what you have to end up
with, not something with an = sign.
Whatever you do to one side of the inequality,
you have to do to the other side
2x+%2B+3y+%3E+6
subtract 2x from both sides
2x+-+2x+%2B+3y+%3E+-2x+%2B+6
3y+%3E+-2x+%2B+6
divide both sides by 3
%283y%29%2F3+%3E+-%282%2F3%29x+%2B+%286%2F3%29
y+%3E+-%282%2F3%29x+%2B+2
This is what you have to graph
+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+-%282%2F3%29x+%2B+2%29+
The solution is everything above the line