SOLUTION: PLEASE HELP ME- FRED BEGINS TO WALK TOWARDS JONS HOUSE AT 3 MI/H. JON LEAVES AT THE SAME TIME AND WALKS TOWARDS FREDS HOUSE ON THE SAME PATH AT 2 MI/H. HOW LONG WILL IT TAKE BEFORE

Algebra ->  Equations -> SOLUTION: PLEASE HELP ME- FRED BEGINS TO WALK TOWARDS JONS HOUSE AT 3 MI/H. JON LEAVES AT THE SAME TIME AND WALKS TOWARDS FREDS HOUSE ON THE SAME PATH AT 2 MI/H. HOW LONG WILL IT TAKE BEFORE      Log On


   



Question 126231: PLEASE HELP ME- FRED BEGINS TO WALK TOWARDS JONS HOUSE AT 3 MI/H. JON LEAVES AT THE SAME TIME AND WALKS TOWARDS FREDS HOUSE ON THE SAME PATH AT 2 MI/H. HOW LONG WILL IT TAKE BEFORE THE TWO WILL MEET IF THE HOUSES ARE 4 MILES APART?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
First think about what is generally true. They meet
somewhere in the middle, so the sum of their walks
is 4 miles. They leave at the same time, so the
time each spends walking is exactly the same.
Now you can start
Let d%5Bf%5D = distance in miles Fred walks
Let d%5Bj%5D = distance in miles Jon walks
d%5Bf%5D+%2B+d%5Bj%5D+=+4 what I just said
Let t = time in hours they both spend walking
d%5Bf%5D+=+3t
d%5Bj%5D+=+2t
Now add these equations
d%5Bf%5D+%2B+d%5Bj%5D+=+3t+%2B+2t
4+=+3t+%2B+2t
5t+=+4
t+=+4%2F5 hr
or
They will meet in %284%2F5%2960+=+48 minutes answer