SOLUTION: I am having a hard time with this question...Solve the following formulas for the given variable {{{V=IIr^2h solve for h}}} The help would be greatly appreciated.

Algebra ->  Equations -> SOLUTION: I am having a hard time with this question...Solve the following formulas for the given variable {{{V=IIr^2h solve for h}}} The help would be greatly appreciated.      Log On


   

Question 122723: I am having a hard time with this question...Solve the following formulas for the given variable V=IIr%5E2h+solve+for+h The help would be greatly appreciated.
Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
Given the equation:
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V+=+pi%2Ar%5E2%2Ah
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Solve for h.
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On the right side recognize that h is multiplied by pi%2Ar%5E2. If you divided the
right side by this multiplier, the right side would become:
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%28%28pi%2Ar%5E2%29%2Ah%29%2F%28pi%2Ar%5E2%29
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But if you divide the right side of an equation by some quantity, you must also divide the
left side by the same quantity to keep the equation in balance. So to keep the given equation
in balance, when we divide the right side by pi%2Ar%5E2 we also divide the left side
by the same quantity and the equation becomes:
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V%2F%28pi%2Ar%5E2%29=+%28%28pi%2Ar%5E2%29%2Ah%29%2F%28pi%2Ar%5E2%29
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On the right side the pi in the numerator cancels with the pi in the denominator,
and the r%5E2 in the numerator cancels with the r%5E2 in the denominator.
As a result of these cancellations, all you are left with on the right side is h. Therefore,
the equation is reduced to:
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V%2F%28pi%2Ar%5E2%29+=+h
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And if you transpose the equation (switch sides) you are left with:
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h+=+V%2F%28pi%2Ar%5E2%29
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and this is what the problem asked you to do ... to solve for h in terms of the other variables
given in the problem.
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Hope this helps you to understand the problem and how you can solve it.
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