SOLUTION: Ed will rent a car for the weekend. He can choose one of two payment plans. The first plan costs$57.96 for two days plus .15 cents per mile. The second plan costs $43.96 for two d
Algebra ->
Equations
-> SOLUTION: Ed will rent a car for the weekend. He can choose one of two payment plans. The first plan costs$57.96 for two days plus .15 cents per mile. The second plan costs $43.96 for two d
Log On
Question 121573: Ed will rent a car for the weekend. He can choose one of two payment plans. The first plan costs$57.96 for two days plus .15 cents per mile. The second plan costs $43.96 for two days plus .20 cents per mile. How many miles does Ed need to drive for the two plans to cost the same? Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! 57.96+.15X=43.96=.20X
.15X-.20X=43.96-57.96
-.05X=-14
X=-14/-.05
X=280 MILES DRIVEN WILL MAKE BOTH PLANS EQUAL.