SOLUTION: Ed will rent a car for the weekend. He can choose one of two payment plans. The first plan costs$57.96 for two days plus .15 cents per mile. The second plan costs $43.96 for two d

Algebra ->  Equations -> SOLUTION: Ed will rent a car for the weekend. He can choose one of two payment plans. The first plan costs$57.96 for two days plus .15 cents per mile. The second plan costs $43.96 for two d      Log On


   



Question 121573: Ed will rent a car for the weekend. He can choose one of two payment plans. The first plan costs$57.96 for two days plus .15 cents per mile. The second plan costs $43.96 for two days plus .20 cents per mile. How many miles does Ed need to drive for the two plans to cost the same?
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
57.96+.15X=43.96=.20X
.15X-.20X=43.96-57.96
-.05X=-14
X=-14/-.05
X=280 MILES DRIVEN WILL MAKE BOTH PLANS EQUAL.