SOLUTION: For h(x) = -2x^2 + x, A. Find the average rate of change from 0 to 3. B. Find an equation of the secant line containing (0,h(0))and (3,h(3)).

Algebra ->  Equations -> SOLUTION: For h(x) = -2x^2 + x, A. Find the average rate of change from 0 to 3. B. Find an equation of the secant line containing (0,h(0))and (3,h(3)).       Log On


   



Question 1208053: For h(x) = -2x^2 + x,

A. Find the average rate of change from 0 to 3.

B. Find an equation of the secant line containing
(0,h(0))and (3,h(3)).

Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
For h(x) = -2x^2 + x, 

A. Find the average rate of change from 0 to .
As x goes from 0 to 3, y [or h(x)] goes from h(0)=-2(0)^2 + 0=0 to h(3)=-2(3)^2 + (3)=-15

From 0 to -15 is a change of (-15)-(0)=-15 in y

From 0 to 3 is a change of (3)-(0) = +3 in x

So the average change in y [or h(x)] per the +3 average change in x
is -15 units change in y per a +3 change in x, which means an average
change of (-15)/(+3)=-5 y-units change per x-units change.

That's what the slope is, the change in y, divided by the change in x 

Answer: -5 change in h(x) y-units per x-unit change.
B. Find an equation of the secant line containing (0, h(0)) and (3, h(3)).
m%22%22=%22%22matrix%281%2C3%2Cchange%2Cin%2Cy%29%2Fmatrix%281%2C3%2Cchange%2Cin%2Cx%29%22%22=%22%22%28-15%29%2F%28%22%22%2B3%29%22%22=%22%22-5

y-y%5B1%5D%22%22=%22%22m%28x-x%5B1%5D%29

y-%280%29%22%22=%22%22-5%28x-%280%29%29

y%22%22=%22%22-5x

change y to h(x)

%22h%28x%29%22%22%22=%22%22-5x



The black line is the secant line. It has two points
in common with the function h(x) (the red curve).

Remember what the word "secant" means, a line that cuts
through a curve, as you can see, the black line cuts through
the red curve, which is the graph of y = h(x). 

[Remember from your geometry that a secant line was a line
that cuts through a circle.] 

Edwin