Question 120731: The length of a rectangle is 2in more than twice its width. If the perimeter of the rectangle is 34in, find the dimensions of the rectangle.
Answer by rapaljer(4671)   (Show Source):
You can put this solution on YOUR website! Let x = width
2x+2= length
2W + 2L = P
2(x)+2(2x+2)=34
2x+4x+4=34
6x+4=34
6x=30
x=5 in Width
2x+2=2(5)+2=12 in Length
Check:
2*5+2*12
=10+24
=34 in
For additional explanations on Word Problems, especially coin problems, please see my website by clicking on my tutor name "rapaljer" anywhere in algebra.com. Click on the first link, which is "Basic and Intermediate Algebra". Look for Basic Algebra, Chapter 1, Section 1.09 and 1.10. For solutions in "LIVING COLOR", look for my "MATH IN LIVING COLOR" page, and click on Basic Algebra, Chapter 1, Sections 1.10.
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