SOLUTION: Find the general form of the equation of a line passing through the point (1,-2) and perpendicular to the line x+3y-6=0.

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Question 1202526: Find the general form of the equation of a line passing through the point (1,-2) and perpendicular to the line x+3y-6=0.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
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passing through the point (1,-2) and perpendicular to the line x+3y-6=0.
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Perpendicularity of the two lines means that this other line should be either 3x-y%2Bk=0, or -3x%2By%2Bj=0.

Pick one of those and then substitute for the given required point and simplify.

3x-y-%283%2A1-%28-2%29%29=0
3x-y-%283%2B2%29=0
3x-y-5=0----------------OR -3x%2By%2B5=0.