SOLUTION: Find dy/dx of (3y^2/(1-3xy)) and find the point on the curve where dy/dx = 0.

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Question 1200749: Find dy/dx of (3y^2/(1-3xy)) and find the point on the curve where dy/dx = 0.
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
y+=++%283y%5E2%29%2F%281-3xy%29

Multiply both sides by (1-3xy)

y%281-3xy%29=3y%5E2

Divide both sides by y

1-3xy=3y

Add 3xy to both sides

1=3y%2B3xy

Factor out 3y on the right side

1=3y%281%2Bx%29

Divide both side by 3(1+x)

1%2F%283%281%2Bx%29%29=y

expr%281%2F3%29%281%2Bx%29%5E%28-1%29=y

-expr%281%2F3%29%281%2Bx%29%5E%28-2%29%281%29=dy%2F%28dx%29

-%281%5E%22%22%29%2F%283%281%2Bx%29%5E2%29=dy%2Fdx

Edwin