SOLUTION: How do you solve: [(3d^2 - 9d + 6) / (2d^2 - 10d + 12)][(6-2d) / (3-3d)]

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Question 1200218: How do you solve:
[(3d^2 - 9d + 6) / (2d^2 - 10d + 12)][(6-2d) / (3-3d)]
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
How do you solve:
[(3d^2 - 9d + 6) / (2d^2 - 10d + 12)][(6-2d) / (3-3d)]
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It's not an equation, so there's nothing to solve.
Might be simplified some:
[(3d^2 - 9d + 6) / (2d^2 - 10d + 12)][(6-2d) / (3-3d)]
= [3*(d-2)*(d-1)/(2*(d-3)*(d-2))]
= [3*(d-1)/(2*(d-3))]
= [3*(d-1)/(2*(d-3))]
= [3/(2*(d-3))]*(2*(d-3)/(3))
= (1/(d-3))*(d-3)
= 1