SOLUTION: Can you help me with this problem? Find three consecutive integers whose sum is 321

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Question 119944: Can you help me with this problem?
Find three consecutive integers whose sum is 321
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
x+(x+1)+(x+2)=321
3x+3=321
3x=321-3
3x=318
x=318/3
x=106 for the first integer.
106+1=107 for the second
106+2=108 for the third
proof
106+107+108=321
321=321