SOLUTION: 8-(2x3-9)= Please take me step by step on how to solve this. 2 to the 4th power plus 2 cubed - 10 divided by (-1) to the 4th power=

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Question 119901This question is from textbook Elementary Algebra Concepts and Applications
: 8-(2x3-9)=
Please take me step by step on how to solve this.

2 to the 4th power plus 2 cubed - 10 divided by (-1) to the 4th power=
This question is from textbook Elementary Algebra Concepts and Applications

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Since you say solve this, the expression must = 0
8 - (2x^3 - 9) = 0
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Removing the brackets changes the signs
8 - 2x^3 + 9 = 0
Which is:
-2x^3 + 17 = 0
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-2x^3 = -17; subtracted 17 from both sides
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Get rid of the negatives, multiply both sides by -1
2x^3 = +17
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x^3 = 17%2F2; divided both sides by 2
x^3 = 8.5
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x = Cube root(8.5)
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x = 2.0408; found 8.5^(1/3) on a calculator
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Check solution, substitute 2.0408 for x in the original equation:
8 - (2(2.0408^3) - 9) =
8 - (2(8.5)-9) =
8 - (17 - 9)
8 - 8 = 0 confirms our solution
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2 to the 4th power plus 2 cubed - 10 divided by (-1) to the 4th power=
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The problem as I see it:
%28%282%5E4+%2B+2%5E3+-+10%29%29%2F%28-1%5E4%29
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First of all remember that -1 to any even numbered power is + 1 so we can ignore the denominator:
%282%5E4+%2B+2%5E3+-+10%29
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Find the values of 2^4; 2*2*2*2 = 16, find the value of 2^3: 2*2*2 = 8
Now we have:
16 + 8 - 10 = +14
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