SOLUTION: The number 4^1000 - 1 is divisible by a) 4 b) 5 c) 7 d) 13 e) 19

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Question 1198925: The number 4^1000 - 1 is divisible by
a) 4 b) 5 c) 7 d) 13 e) 19

Found 2 solutions by greenestamps, ikleyn:
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


ANSWER: b) 5

Look at the pattern of remainders when 4^n-1 is divided by 5:

4^1-1 = 3; remainder when divided by 5 is 3
4^2-1 = 15; remainder when divided by 5 is 0
4^3-1 = 63; remainder when divided by 5 is 3
4^4-1 = 255; remainder when divided by 5 is 0

The pattern repeats forever; the remainder when 4^1000-1 is divided by 5 is 0.

You can find the similar patterns of remainders when 4^n-1 is divided by 7, 13, or 19; the length of the repeating patterns is such that 4^1000-1 will not be divisible by any of those other answer choices.


Answer by ikleyn(52787) About Me  (Show Source):
You can put this solution on YOUR website!
.
The number 4^1000 - 1 is divisible by
a) 4 b) 5 c) 7 d) 13 e) 19
~~~~~~~~~~~~~~~

(a)  Regarding (a), it is clear that the remainder of division  4%5E1000-1  by 4 is -1, 

     which is the same as 3 mod(4);  so,  4%5E1000-1  is not divisible by 4.



(b)  Regarding (b),  4%5E1000-1 = %284%5E2%29%5E500-1 is divisible by 4%5E2-1 = 15;

     so,  4%5E1000-1  is divisible by 5.



(c, d, e)  Regarding (c), (d) and (e), I prepared a table below, which shows the remainders

     of division 4%5Ek  by 7, 13 and 19 respectively.


       k      4%5Ek mod(7)      4%5Ek mod(13)         4%5Ek mod(13)
   ---------------------------------------------------------------

       1	  4	           4	               4
       2	  2	           3	              16
       3	  1	          12	               7
       4	  4	           9	               9
       5	  2	          10	              17
       6	  1	           1	              11
       7	  4	           4	               6
       8	  2	           3	               5
       9	  1	          12	               1
      10	  4	           9	               4
			
	          3	           6	               9   <<<---===  the length of the period.


     The table shows that for each of these divisors, 7, 13, 19,  the sequence of remainders 
     is periodical, as it should be.

     Each period (in each column) starts from the very first term of the sequence.


     For mod(7), the remainder 1 is every 3rd term of the sequence.
     Since the index/(the degree) of 1000 is not a multiple of 3,  4%5E1000 mod(7) is not 1;
     hence,  4%5E1000-1  is not divisible by 7.


     For mod(13), the remainder 1 is every 6th term of the sequence.
     Since the index/(the degree) of 1000 is not a multiple of 6,  4%5E1000 mod(13) is not 1;
     hence,  4%5E1000-1  is not divisible by 13.


     For mod(19), the remainder 1 is every 9th term of the sequence.
     Since the index/(the degree) of 1000 is not a multiple of 9,  4%5E1000 mod(19) is not 1;
     hence,  4%5E1000-1  is not divisible by 19.


ANSWER.    (a)  is not divisible.

           (b)  is divisible.

           (c)  is not divisible.

           (d)  is not divisible.

           (e)  is not divisible.

Solved.