Question 1197446: hello please help me to solve this,thankyou!!
two hoses, when connected to a swimming pool, can fill the pool in 4 hours. If the larger hose alone is used, it can fill the pool in 6 hours less than the smaller hose how long will it take the smaller hose to fill the swimming pool alone?
Found 3 solutions by MathLover1, josgarithmetic, MathTherapy: Answer by MathLover1(20849) (Show Source): Answer by josgarithmetic(39617) (Show Source): Answer by MathTherapy(10551) (Show Source):
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hello please help me to solve this,thankyou!!
two hoses, when connected to a swimming pool, can fill the pool in 4 hours. If the larger hose alone is used, it can fill the pool in 6 hours less than the smaller hose how long will it take the smaller hose to fill the swimming pool alone?
Let time the smaller hose takes be S
Then time the larger hose takes = S - 6
Since both, when turned on, fills it in 4 hours, we get:
4(S - 6) + 4S = S(S - 6) ------ Multiplying by LCD, 4S(S - 6)
0 = (S - 12)(S - 2)
Time the smaller hose takes, working alone, or or S = 2 hours (ignore)
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