SOLUTION: Can you help me with this problem? Find the value of the change in a purse that contains twice as many nickels as pennies, 3 more dimes than nickels, and as many quarters as dim

Algebra ->  Equations -> SOLUTION: Can you help me with this problem? Find the value of the change in a purse that contains twice as many nickels as pennies, 3 more dimes than nickels, and as many quarters as dim      Log On


   

Question 119699: Can you help me with this problem?
Find the value of the change in a purse that contains twice as many nickels as pennies, 3 more dimes than nickels, and as many quarters as dimes and nickels combined. Express your answer in terms of p, the number of pennies
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
n = number of nickels
d = number of dimes
p =number of pennies
q = number of quarters
v = value of all the coins in purse
n+=+2p
d+=+n+%2B+3
q+=+n+%2B+d
The number of coins in the purse is:
p+%2B+n+%2B+d+%2B+q
The value of all the coins in the purse is:
v+=+1%2Ap+%2B+5%2An+%2B+10%2Ad+%2B+25%2Aq
n+=+2p, so
v+=+p+%2B+5%2A%282p%29+%2B+10%2Ad+%2B+25%2Aq
d+=+n+%2B+3 so,
v+=+p+%2B+10p+%2B+10%28n+%2B+3%29+%2B+25%2Aq
remember, n+=+2p
v+=+11p+%2B+10%282p+%2B+3%29+%2B+25%2Aq
Also, q+=+n+%2B+d
That's the same as
q+=+2p+%2B+%282p+%2B+3%29
q+=+4p+%2B+3
v+=+11p+%2B+20p+%2B+30+%2B+25%284p+%2B+3%29
v+=+21p+%2B+30+%2B+100p+%2B+75
v+=+121p+%2B+105 answer