SOLUTION: Philip is twice as old as Lori. In y years he will be 1.5 times as old as Lori. Lori's age at present may be correctly expressed as: y/4, 2y/3, y, 3y/2, 3y

Algebra ->  Equations -> SOLUTION: Philip is twice as old as Lori. In y years he will be 1.5 times as old as Lori. Lori's age at present may be correctly expressed as: y/4, 2y/3, y, 3y/2, 3y      Log On


   



Question 1195503: Philip is twice as old as Lori. In y years he will be 1.5 times as old as Lori. Lori's age at present may be correctly expressed as:
y/4, 2y/3, y, 3y/2, 3y

Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Philip,2x
Lori,x


y more years pass.

2x%2By=1.5%28x%2By%29

4x%2B2y=3x%2B3y------do you understand how? Now just finish solving for x.

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
Philip is twice as old as Lori. In y years he will be 1.5 times as old as Lori.
Lori's age at present may be correctly expressed as:
y/4, 2y/3, y, 3y/2, 3y.
~~~~~~~~~~~~~~~~

If Lori's current age is x, then Philip's current age is 2x, according to the problem.


Next, in y years, Philip's age will be  (2x+y);  Lori's age will be  (x+y) years.


The problem says that  

    2x + y = 1.5*(x+y).


It gives

    2x + y = 1.5x + 1.5y

    2x - 1.5x = 1.5y - y

      0.5x    =   0.5y

         x    =      y

    +----------------------------------------------------+
    |    Thus Lori's current age (x) is y years;         |
    |    so, Lori's current age can be expressed as y    | 
    |    (the third option of the given answers list).   |
    +----------------------------------------------------+

Solved.

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It is good problem to check whether you do understand in full
what you write, when you solve the problem.