SOLUTION: Hello! i have a three part question i cannot figure out the last part of, any input would be so helpful thank you in advance! (a) Graph the given​ function, ​(b) find all valu

Algebra ->  Equations -> SOLUTION: Hello! i have a three part question i cannot figure out the last part of, any input would be so helpful thank you in advance! (a) Graph the given​ function, ​(b) find all valu      Log On


   

Question 1195062: Hello! i have a three part question i cannot figure out the last part of, any input would be so helpful thank you in advance!
(a) Graph the given​ function, ​(b) find all values of x where the function is​ discontinuous, and ​(c) find the limit from the left and the right at any values of x where the function is discontinuous.
{6 if x<-1
g(x){x^2-3 if -1<(or =) x <(or =) 3
{6 if x>3
B.
The function is discontinuous at -1
C. Find the limit or limits from the left and from the right for any values of x found in part​ (b).
The​ limit(s) from the left​ is/are ____ The​ limit(s) from the right​ is/are
  
____.
(Use a comma to separate answers as​ needed.)
Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
.

As I understand from your post, you need help only in part (C).

My explanations to this part are below. 


(C)  The limit of the function  g(x)  from the left at  x ---> -1  is  -6.      ANSWER



     The limit from the right of the function  g(x)  at x ---> -1  is
   
     the value of the function  (x^2 -3)  at x= -1  (-1)^2 - 3 = 1 - 3 = -2.    ANSWER

Solved, answered and explained.