SOLUTION: For this equation, x is real, b and c are each real constants, and b is less than c. What are the possible values of x so that y = ((x^2) - bc)((2x - b - c)^-1)?

Algebra ->  Equations -> SOLUTION: For this equation, x is real, b and c are each real constants, and b is less than c. What are the possible values of x so that y = ((x^2) - bc)((2x - b - c)^-1)?      Log On


   



Question 1188289: For this equation, x is real, b and c are each real constants, and b is less than c. What are the possible values of x so that y = ((x^2) - bc)((2x - b - c)^-1)?
Found 2 solutions by Edwin McCravy, ikleyn:
Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
y+=+%28x%5E2+-+bc%29%28%282x+-+b+-+c%29%5E%28-1%29%29

y+=+%28x%5E2+-+bc%29%2F%282x+-+b+-+c%29%29

The denominator cannot equal zero, so

2x-b-c%22%22%3C%3E%22%220

2x%22%22%3C%3E%22%22b%2Bc

x%22%22%3C%3E%22%22%28b%2Bc%29%2F2

Edwin

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.

This  " problem "  goes with  TERRIBLE  wording,

which discloses mathematical illiteracy of its creator / composer.