SOLUTION: Find the sum of the series 15/42+15/56+15/72+15/90+…+15/9900

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Question 1186693: Find the sum of the series 15/42+15/56+15/72+15/90+…+15/9900
Answer by ikleyn(52776) About Me  (Show Source):
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Find the sum of the series 15/42+15/56+15/72+15/90+…+15/9900
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The series is 15 times  S = 1%2F42+%2B+1%2F56+%2B+1%2F72+%2B+1%2F90+%2B+ellipsis+%2B+1%2F9900


Each addend in the sum S is


    1%2F42 = 1%2F6+-+1%2F7         (1)

    1%2F56 = 1%2F7+-+1%2F8       
    
    1%2F72 = 1%2F8+-+1%2F9

    1%2F90 = 1%2F9+-+1%2F10

       . . . and so on . . . 

    1%2F9900 = 1%2F99+-+1%2F100     (last)


The pattern is clear.


When you add the lines from (1) to the (last),  all  intermediate terms with opposite signs will cancel each other, 

leaving only  1%2F6+-+1%2F100 = %28100-6%29%2F600 = 94%2F600.


So the ANSWER to the problem's question is  15%2A%2894%2F600%29 = 94%2F40 = 47%2F20 = 2.35.

Solved, answered and explained.