SOLUTION: Simplify the following and state any restrictions on the variable. 9x^2 - 64/x^2+7x+12 ÷ 3x^2+17x+24/x^2+6x+9

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Question 1186675: Simplify the following and state any restrictions on the variable.
9x^2 - 64/x^2+7x+12 ÷ 3x^2+17x+24/x^2+6x+9

Found 2 solutions by Alan3354, Edwin McCravy:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Simplify the following and state any restrictions on the variable.
9x^2 - 64/x^2+7x+12 ÷ 3x^2+17x+24/x^2+6x+9
----------------
9x%5E2+-+64%2Fx%5E2%2B7x%2B12 ÷ 3x%5E2%2B17x%2B24%2Fx%5E2%2B6x%2B9
------------
Add parentheses.
They're free.

Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
He's right about the parentheses when typing numerators and denominators all
on one line. Otherwise, you can't tell where a numerator or denominator starts
and ends.  Here is how you should have typed your problem:

((9x^2 - 64)/(x^2+7x+12)) ÷ ((3x^2+17x+24)/(x^2+6x+9))

Correct punctuation is even more important in math than in English. Anyways,
I'll assume what I think you meant to be a numerator and a denominator, and
where I think you meant for them to be.

----------------------------------------------------------

Even after we simplify the expression, we must make restrictions to make sure
that there are no numbers we could substitute for x that would cause the
original expression to be undefined by dividing by 0. 

Therefore, 
EACH TIME WE CANCEL ANY FACTOR, WE MUST MAKE A RESTRICTION THAT PREVENTS THE
CANCELED EXPRESSION FROM EVER BEING EQUAL TO ZERO.  ALSO IN THE FINAL
SIMPLIFICATION, WE MUST MAKE A RESTRICTION THAT PREVENTS ITS DENOMINATOR
FROM BEING EQUAL TO ZERO.

%289x%5E2+-+64%29%2F%28x%5E2%2B7x%2B12%29 ÷ %283x%5E2%2B17x%2B24%29%2F%28x%5E2%2B6x%2B9%29 

Invert and multiply:

%28%289+x%5E2+-+64%29%2F%28x%5E2+%2B+7+x+%2B+12%29%29%22%22%2A%22%22%28%28x%5E2+%2B+6+x+%2B+9%29%2F%283+x%5E2+%2B+17+x+%2B+24%29%29

Factor:
%28%283x-8%29%283x%2B8%29%2F%28x%2B4%29%28x%2B3%29%29%22%22%2A%22%22%28%28x%2B3%29%28x%2B3%29%2F%28x%2B3%29%283x%2B8%29%29

We cancel the (3x+8)'s
3x%2B8%3C%3E0%7D%7D%0D%0A%7B%7B%7B3x%3C%3E-8
x%3C%3E-8%2F3

We must indicate the restriction that x cannot equal -8/3.

%28%283x-8%29%28cross%283x%2B8%29%29%2F%28x%2B4%29%28x%2B3%29%29%22%22%2A%22%22%28%28x%2B3%29%28x%2B3%29%2F%28x%2B3%29%28cross%283x%2B8%29%29%29

We cancel one of the (x+3)'s and indicate the restriction
x%2B3%3C%3E0
x%3C%3E-3

%28%283x-8%29%28cross%283x%2B8%29%29%2F%28x%2B4%29%28cross%28x%2B3%29%29%29%22%22%2A%22%22%28%28cross%28x%2B3%29%29%28x%2B3%29%2F%28x%2B3%29%28cross%283x%2B8%29%29%29

We cancel the other pair of (x+3)'s.  [We've already indicated this restriction,
so we don't need to indicate it again.]

%28%283x-8%29%28cross%283x%2B8%29%29%2F%28x%2B4%29%28cross%28x%2B3%29%29%29%22%22%2A%22%22

The final simplification is

%283x-8%29%2F%28x%2B4%29

We must also indicate that the denominator of the final simplification to
prevent it from ever being 0.

x%2B4%3C%3E0
x%3C%3E-4

So putting in all the restrictions:



Edwin