= (1)
= 1. (2)
Introduce new variables u = , v = . with these variables, the equations take the form
3u - 4v = (3)
2u - 5v = 1. (4)
To solve it use the Elimination method.
6u - 8v = (5)
6u - 15v = 3 (6)
------------------------------- Subtract eq(5) from eq(6)
-7v = 2 =
v = .
Substitute v = -1/3 into equation (6) to get
6u = 3 - 5 = -2,
u = = .
ANSWER. x = = = -3. y = = = -3.
Solved.
Introducing new variables is one of standard methods solving such equations.