Question 1184587: The value of a in the standard form of the equation (x + 7)² - 6 = 5°
Found 4 solutions by ankor@dixie-net.com, ikleyn, josgarithmetic, greenestamps:
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! The value of a in the standard form of the equation (x + 7)² - 6 = 5°
(x+7)(x+7) - 6 = 5
FOIL
x^2 + 14x + 49 - 6 - 5
x^2 + 14x + 38 = 0
:
the standard form ax^2 + bx + c, so a = 1
Answer by ikleyn(52777)  (Show Source):
You can put this solution on YOUR website! .
The standard form of a quadratic equation ONLY defines the form of the equation,
but DOES NOT DEFINE the values of the coefficients.
The values of the coefficients can be all multiplied by any non-zero coefficient, leaving the equation EQIVALENT;
THEREFORE, the values of the coefficients in the standard form quadratic equation are defined only accurate to the common non-zero multiplier.
Therefore, all your attempts to "invent" a new class of Algebra problems are empty and make no sense.
Answer by josgarithmetic(39617)  (Show Source):
Answer by greenestamps(13198)  (Show Source):
You can put this solution on YOUR website!
IF by standard form you mean
y=ax^2+bx+c
then the question can be answered.
Note, however, that the standard form for a quadratic is not always expressed in that form. So it is technically a defective post if you simply ask for the value of a.
And if you are indeed talking about that standard form, there is no need to expand and/or simplify the entire equation.
a is the coefficient of the x^2 term and is simply the product of the constant coefficient (if any) and the coefficients of the x terms in each binomial factor.
In your example the constant coefficient is 1, and there are two binomial factors, both of which have coefficient 1. So the value of a is
(1)(1)(1) = 1.
ANSWER: a=1
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