SOLUTION: please help me solve {{{2^2^(x^2-3)*2^3x=16}}} show that {{{2x^2+3x-10=0}}}

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Question 1182949: please help me solve
2%5E2%5E%28x%5E2-3%29%2A2%5E3x=16
show that 2x%5E2%2B3x-10=0
Found 2 solutions by Boreal, ikleyn:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
2^2(x^2-3)*2^3*x=2^4, so the base may be removed from all terms.
2x^2-6+3x=4
2^x^2+3x-10=0

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.

Your original equation is written  INCORRECTLY.

So, I insistently advise you to re-post it in correct form.