SOLUTION: please help me solve {{{4x^2-2x-3=0 }}}

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Question 1182091: please help me solve
4x%5E2-2x-3=0+
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

4x%5E2-2x-3=0+....use quadratic formula

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+.... in your case a=4, b=-2, and c=-3
x+=+%28-%28-2%29+%2B-+sqrt%28+%28-2%29+%5E2-4%2A4%2A%28-3%29++%29%29%2F%282%2A4%29+
x+=+%282+%2B-+sqrt%28+4%2B48++%29%29%2F8+
x+=+%282+%2B-+sqrt%28+52+%29%29%2F8+
x+=+%282+%2B-+2sqrt%2813%29%29%2F8+....simplify
x+=+%281+%2B-+sqrt%2813%29%29%2F4+

exact solutions:
x+=+1%2F4+%2B+sqrt%2813%29%2F4+
x+=+1%2F4+-+sqrt%2813%29%2F4+
approximate solutions:
x+=+1.15
x+=-0.65