SOLUTION: Hello out there,I need help with two tough problems,the first one is,Solve:3y/2=7+y/4.And the last one is,Find the quotient:e^2-e-12/e-4,thanks to whoever can help.

Algebra ->  Equations -> SOLUTION: Hello out there,I need help with two tough problems,the first one is,Solve:3y/2=7+y/4.And the last one is,Find the quotient:e^2-e-12/e-4,thanks to whoever can help.      Log On


   

Question 118183: Hello out there,I need help with two tough problems,the first one is,Solve:3y/2=7+y/4.And the last one is,Find the quotient:e^2-e-12/e-4,thanks to whoever can help.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
#1



3y%2F2=7%2By%2F4 Start with the given equation



%284%29%283y%2F2%29=%284%29%287%2By%2F4%29 Multiply both sides by the LCM of 4. This will eliminate the fractions (note: if you need help with finding the LCM, check out this solver)



6y=28%2By Distribute and multiply the LCM to each side



6y=28%2By Combine like terms on the right side


6y-y=28 Subtract y from both sides


5y=28 Combine like terms on the left side


y=%2828%29%2F%285%29 Divide both sides by 5 to isolate y



y=28%2F5 Reduce

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Answer:
So our answer is y=28%2F5 (which is approximately y=5.6 in decimal form)






#2




%28e%5E2-e-12%29%2F%28e-4%29 Start with the given expression

%28%28e-4%29%28e%2B3%29%29%2F%28e-4%29 Factor e%5E2-e-12 to get %28e-4%29%28e%2B3%29


%28e-4%29%28e%2B3%29%2F%28e-4%29 Combine the fractions


cross%28%28e-4%29%29%28e%2B3%29%2Fcross%28%28e-4%29%29 Cancel like terms


e%2B3 Simplify


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Answer:

So %28e%5E2-e-12%29%2F%28e-4%29 simplifies to e%2B3. In other words %28e%5E2-e-12%29%2F%28e-4%29=e%2B3