SOLUTION: 3(e+4)-(3e+12)=0 0=0 What is the answer called? Is it the real numbers or the null set?

If you accurately simplify it, you will get the identity

    0 = 0,

which is always valid.



It means that the original equation is valid for ANY value of "e", i.e. has INFINITELY MANY SOLUTIONS.


Any real number "e" is the solution to the original equation.



Or, in other words, the original equation is, actually, an IDENTITY.