SOLUTION: Molly bought $5.28 worth of oranges and $8.80 worth of apples. She bought 2 more pounds of oranges than apples. if apples cost twice as much per pound than oranges, how much pounds

Algebra ->  Equations -> SOLUTION: Molly bought $5.28 worth of oranges and $8.80 worth of apples. She bought 2 more pounds of oranges than apples. if apples cost twice as much per pound than oranges, how much pounds      Log On


   

Question 1180214: Molly bought $5.28 worth of oranges and $8.80 worth of apples. She bought 2 more pounds of oranges than apples. if apples cost twice as much per pound than oranges, how much pounds of each did she buy?
Answer by greenestamps(13198) About Me  (Show Source):
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2 more pounds of oranges than apples:
x = pounds of apples
x+2 = pounds of oranges

Apples cost twice as much per pound as oranges:
y = cost per pound of oranges
2y = cost per pound of apples

%28x%29%282y%29=8.80 the total cost of the apples
2xy=8.80
xy=4.40

%28x%2B2%29%28y%29=5.28 the total cost of the oranges
xy%2B2y=5.28

4.40%2B2y=5.28
2y=0.88
y=0.44

x%28.44%29=4.40
x=10

ANSWER:
x=10 pounds of apples (at $0.88 per pound)
x+2=12 pounds of oranges (at $0.44 per pound)

CHECK:
cost of apples: 10($0.88)=$8.80
cost of oranges: 12($0.44)=$5.28