SOLUTION: The perimeter of a rectangle is 30 ft and the width is 5 ft. Find the ratio of the length of the rectangle to its width. Can I have help with this?

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Question 1180089: The perimeter of a rectangle is 30 ft and the width is 5 ft. Find
the ratio of the length of the rectangle to its width.
Can I have help with this?
Found 2 solutions by MathLover1, josgarithmetic:
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

given:
The perimeter of a rectangle is
30ft+ and
the width is 5ft

first find the length of the rectangle
The perimeter of a rectangle is
p=2%28L%2BW%29...substitute given values
2%28L%2B5ft%29=30ft...both sides divide by 2
%28L%2B5ft%29=15ft
L=15ft-5ft
L=10ft


the ratio of the length of the rectangle to its width is 10%3A5=2%3A1


Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Perimeter, 30 feet
Width, 5 feet

2%2ALENGTH=30-2%2A5
2%2ALENGTH=20
Length is 10 feet.


Ratio length to width, 10%2F5=highlight%282%2F1%29